/*
 * bigbin.c -  display big binary time
 *
 * Copyright (C) 2003 Nathan Laredo (laredo@gnu.org)
 *
 * This program is free software; you can redistribute it and/or modify
 * it under the terms of the GNU General Public License as published by
 * the Free Software Foundation; either version 2 of the License, or
 * (at your option) any later version.
 *
 * This program is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
 * GNU General Public License for more details.
 *
 * You should have received a copy of the GNU General Public License
 * along with this program; if not, write to the Free Software
 * Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA.
 *
 */

#include <stdio.h>
#include <time.h>

static char *digits[2] = {
" 000000 " "00000000" "00    00" "00    00"
"00    00" "00    00" "00000000" " 000000 ",

"   11   " " 1111   " "   11   " "   11   "
"   11   " "   11   " " 111111 " " 111111 ",
};

static void paintchar(char *ch, int x, int y)
{
	int i;
	char line[9];

	line[8] = '\0';
	for (i = 0; i < 8; i++) {
		fprintf(stderr, "\E[%d;%dH", y + i + 1, x + 1);
		strncpy(line, ch + i * 8, 8);
		fprintf(stderr, line);
	}
}

int main(int argc, char **argv)
{
	time_t now;
	struct tm *tmp;
	int val[6 * 3], oldval[6 * 3];
	int i;

	fprintf(stderr, "\E[H\E[2J");

	for (i = 0; i < 6 * 3; i++) {
		oldval[i] = 117;
	}
	while (1) {
		now = time(NULL);
		tmp = localtime(&now);
		for (i = 0; i < 6; i++) {
			val[i] = ((tmp->tm_hour & (1<<(5-i))) != 0);
			val[i + 6] = ((tmp->tm_min & (1<<(5-i))) != 0);
			val[i + 12] = ((tmp->tm_sec & (1<<(5-i))) != 0);
		}
		for (i = 0; i < 6 * 3; i++) {
			if (val[i] != oldval[i]) {
				paintchar(digits[val[i]],
					  (i % 6) * 9, 9 * (i / 6));
			}
		}
		sleep(1);
		memcpy(oldval, val, sizeof(val));
	}
	exit(0);
}